Accenture Coding Questions and Answers With Important Topics

Here is the Accenture coding test syllabus that you might encounter in a technical assessment or interview:

• Basics of Programming
• Input and Output Concepts
• Flow Control
• Conditional Looping
• Arrays
• Strings
• Linked Lists
• Stacks and Queues
• Trees
• Graphs
• Dynamic Programming
• Sorting and Searching
• Backtracking

Accenture’s coding assessment consists of questions that vary across difficulty levels and topic coverage. Familiarizing yourself with each level will allow you to tailor your preparation, as well as aid your pacing throughout the test.

Difficulty Levels:

• Beginner (Warm-Up Questions): These will evaluate your knowledge of basic programming constructs like loops, conditionals, and basic functions. You may be evaluated on converting numbers between different number bases, or solving logic and math questions to help "warm you up."
• Medium: Questions in this category will often require knowledge of the fundamentals of data structures (arrays, strings, linked lists) and algorithms (sorting, searching, or recursion). You may be challenged with dynamic programming, backtracking, or a more complex problem-solving format.
• Hard: Advanced questions may focus on complex algorithms, system design, or object-oriented programming (OOP) concepts. These are less common but may appear for advanced roles or as tie-breakers.

Bottom line: Accenture’s technical and cognitive assessments are designed to evaluate both your foundational knowledge and your ability to solve more complex problems under time constraints.

Duration: 45 minutes.

Number of Questions: Typically 2 coding problems.

Difficulty Level: Easy - Medium.

Languages Allowed: C, C++, Java, Python.

Rules for Accenture Coding Questions

Here are the rules to be followed while answering Accenture coding questions:

• You must write the entire program without any pre-existing code.
• You need to write the code for the given problem statements. Once done, run the program to see the output.
• To assist you in debugging, any errors in your code will be shown.
• To pass this section, you typically need one clear output and one partial output.

Programming Languages Allowed

Commonly Allowed Languages:

• C
• C++
• Java
• Python

For certain positions, or for some coding rounds, you may be able to use a different language, such as C# or JavaScript, although the main language options are C, C++, Java, and Python. Always confirm the latest instructions on your test platform or with your invite, as the allowed programming languages may change from time to time.

Key Points:

• You can choose your desired language for every coding question.
• All solutions are marked using automated test cases, so make sure your code works as expected in your choice of language.
• It's good to get familiarised with the syntax of the language you decide to use, in addition to how to directly do standard input and output, in order to avoid opportunities for error in your coding test.

Understanding the marking scheme of the Accenture coding round and key rules will help you score well and reduce wasting marks.

How is the Accenture coding round scored?

The coding round typically consists of two questions to be solved in 45 minutes. Each question is evaluated based on how many test cases your solution passes. To clear the round, you generally need to:

• Achieve a complete output for at least one question (all test cases passed).
• Achieve a partial output for the second question (some test cases passed).

Is there negative marking?

No, the marking is not negative. It is recommended that you answer both questions and aim to pass as many test cases as possible.

What are the main rules and guidelines?

• You must write the entire code from scratch; no pre-written code is provided.
• You can select your choice of programming language from the allowed options (such as C, C++, Java, Python).
• All solutions are evaluated automatically against a set of sample and hidden test cases.
• Throughout the test, you can compile, execute, and debug your code.
• Plagiarism or copying code from others is strictly prohibited and can result in disqualification.
• Use only standard libraries available in your chosen language.

What is required to clear the coding round?

You should aim to pass all test cases for at least one problem and as many as possible for the other. This demonstrates both accuracy and problem-solving ability.

What We Have Discussed So Far – Quick Recap of Accenture Coding Questions

• Duration & Format: 45 minutes, 2 coding problems, difficulty: Easy–Medium.
• Languages Allowed: C, C++, Java, Python (sometimes C# or JavaScript for specific roles).
• Rules:
  
  • Develop your code independently; no existing code can be used.
  • You can run and debug your code during the exam.
  • Each solution will be graded automatically based on a mix of sample and hidden test cases.
  • Plagiarism is not ok.
• Scoring:
  
  • Pass all test cases for one question and partial for the other.
  • No negative marking.
• Key Tips:
  
  • Pick the language you are most comfortable with and ensure you get the syntax correct in regard to input/output.
  • Make sure you are correct and become a great problem solver, this will allow you to pass more test cases.

Accenture often uses a variety of coding challenges to test your problem-solving skills. Here’s a list of beginner-level Accenture coding questions:

1. The royal baker needs to prepare a special cake. Each ingredient has a specific weight. The baker wants to know the total weight of the ingredients and the heaviest ingredient used.

Input Format

• The weights of the ingredients are given in a list of floating-point numbers.

Output Format

• Two floating-point numbers indicate the weight of the heaviest ingredient and the total weight.

Example

Input: [1.2, 0.5, 2.3, 1.8] Output: (5.8, 2.3)

Python

def cake_ingredients(weights):
    if not weights:
        return 0, 0
    total_weight = sum(weights)
    heaviest = max(weights)
    return total_weight, heaviest

print(cake_ingredients([1.2, 0.5, 2.3, 1.8]))

Java

public class Main {
    public static double[] cakeIngredients(double[] weights) {
        if (weights.length == 0)
            return new double[]{0, 0};
        double totalWeight = 0;
        double heaviest = weights[0];
        for (double weight : weights) {
            totalWeight += weight;
            if (weight > heaviest)
                heaviest = weight;
        }
        return new double[]{totalWeight, heaviest};
    }

    public static void main(String[] args) {
        double[] results = cakeIngredients(new double[]{1.2, 0.5, 2.3, 1.8});
        System.out.println("Total Weight: " + results[0] + ", Heaviest Ingredient: " + results[1]);
    }
}

C

#include <stdio.h>

void cakeIngredients(double weights[], int size, double* totalWeight, double* heaviest) {
    if (size == 0) {
        *totalWeight = 0;
        *heaviest = 0;
        return;
    }
    *totalWeight = 0;
    *heaviest = weights[0];
    for (int i = 0; i < size; i++) {
        *totalWeight += weights[i];
        if (weights[i] > *heaviest)
            *heaviest = weights[i];
    }
}

int main() {
    double weights[] = {1.2, 0.5, 2.3, 1.8};
    double totalWeight, heaviest;
    cakeIngredients(weights, 4, &totalWeight, &heaviest);
    printf("Total Weight: %.2f, Heaviest Ingredient: %.2f\n", totalWeight, heaviest);
    return 0;
}

2. Inside a magical garden, flowers bloom in a number of colors, and each one has a particular point value. You will find the total points based on what the gardener has picked.

Input Format

• A list of integers representing the points for each flower.

Output Format

• An integer representing the total points earned from the flowers.

Example

Input: [5, 3, 8, 2] Output: 18

Python

def total_flower_points(flowers):
    total_points = 0
    for points in flowers:
        total_points += points
    return total_points

if __name__ == "__main__":
    print(total_flower_points([5, 3, 8, 2]))

Java

public class Main {
    public static int totalFlowerPoints(int[] flowers) {
        int totalPoints = 0;
        for (int points : flowers) {
            totalPoints += points;
        }
        return totalPoints;
    }

    public static void main(String[] args) {
        System.out.println(totalFlowerPoints(new int[]{5, 3, 8, 2}));
    }
}

C

#include <stdio.h>

int totalFlowerPoints(int flowers[], int size) {
    int totalPoints = 0;
    for (int i = 0; i < size; i++) {
        totalPoints += flowers[i];
    }
    return totalPoints;
}

int main() {
    int flowers[] = {5, 3, 8, 2};
    printf("%d\n", totalFlowerPoints(flowers, 4));
    return 0;
}

3. A wizard brews a secret potion with different magical ingredients, each having a unique integer ID. Your job is to determine if a particular ID was used in the potion.

Input Format

• A list of integers representing the ingredient IDs and an integer representing the ID to check.

Output Format

• A string indicating whether the ingredient ID is used ("Yes" or "No").

Example

Input: [101, 102, 103, 104], 102 Output: Yes

Python

def check_ingredient(ingredients, id_to_check):
    return "Yes" if id_to_check in ingredients else "No"

print(check_ingredient([101, 102, 103, 104], 102))

Java

import java.util.Arrays;

public class Main {
    public static String checkIngredient(int[] ingredients, int idToCheck) {
        return Arrays.stream(ingredients).anyMatch(id -> id == idToCheck) ? "Yes" : "No";
    }

    public static void main(String[] args) {
        System.out.println(checkIngredient(new int[]{101, 102, 103, 104}, 102));
    }
}

C

#include <stdio.h>

const char* checkIngredient(int ingredients[], int size, int idToCheck) {
    for (int i = 0; i < size; i++) {
        if (ingredients[i] == idToCheck) {
            return "Yes";
        }
    }
    return "No";
}

int main() {
    int ingredients[] = {101, 102, 103, 104};
    printf("%s\n", checkIngredient(ingredients, 4, 102));
    return 0;
}

4. A timekeeper has a collection of clocks, each representing a specific hour. Your task is to calculate the total hours represented by the clocks and find the clock showing the highest hour.

Input Format

• A list of integers representing the hours of the clocks.

Output Format

• Two integers: the total hours and the highest hour.

Example

Input: [3, 7, 5, 9] Output: (24, 9)

Python

def timekeeper_clocks(clocks):
    total_hours = sum(clocks)
    highest_hour = max(clocks)
    return total_hours, highest_hour

print(timekeeper_clocks([3, 7, 5, 9]))

Java

public class Main {
    public static int[] timekeeperClocks(int[] clocks) {
        int totalHours = 0;
        int highestHour = clocks[0];
        for (int hour : clocks) {
            totalHours += hour;
            if (hour > highestHour)
                highestHour = hour;
        }
        return new int[]{totalHours, highestHour};
    }

    public static void main(String[] args) {
        int[] result = timekeeperClocks(new int[]{3, 7, 5, 9});
        System.out.println("(" + result[0] + ", " + result[1] + ")");
    }
}

C

#include <stdio.h>

void timekeeperClocks(int clocks[], int size, int* totalHours, int* highestHour) {
    *totalHours = 0;
    *highestHour = clocks[0];
    for (int i = 0; i < size; i++) {
        *totalHours += clocks[i];
        if (clocks[i] > *highestHour)
            *highestHour = clocks[i];
    }
}

int main() {
    int clocks[] = {3, 7, 5, 9};
    int totalHours, highestHour;
    timekeeperClocks(clocks, 4, &totalHours, &highestHour);
    printf("Total Hours: %d, Highest Hour: %d\n", totalHours, highestHour);
    return 0;
}

Intermediate-Level Python Coding Questions

This set of questions is intended for testing your skills with arrays, strings, and basic algorithms that require logic and problem-solving. They usually require calculations like average finish time, maximum finish time, minimum finish time, or finishing ranges.

5. In a race, each participant's finish time is recorded. You need to find out who finished first and how long it took them. Additionally, you need to find the average finish time of all participants.

Input Format

• A list of floating-point numbers representing finish times.

Output Format

• Two floating-point numbers: the first-place time and the average time.

Example

Input: [12.5, 10.0, 11.2, 13.3] Output: (10.0, 11.5)

Python

def race_results(times):
    if not times:
        return None, 0
    first_place_time = min(times)
    average_time = sum(times) / len(times)
    return first_place_time, average_time

print(race_results([12.5, 10.0, 11.2, 13.3]))

Java

public class Main {
    public static double[] raceResults(double[] times) {
        if (times.length == 0)
            return new double[]{-1, 0};
        double firstPlaceTime = times[0];
        double totalTime = 0;
        for (double time : times) {
            if (time < firstPlaceTime)
                firstPlaceTime = time;
            totalTime += time;
        }
        double averageTime = totalTime / times.length;
        return new double[]{firstPlaceTime, averageTime};
    }

    public static void main(String[] args) {
        double[] results = raceResults(new double[]{12.5, 10.0, 11.2, 13.3});
        System.out.println("First Place Time: " + results[0] + ", Average Time: " + results[1]);
    }
}

C

#include <stdio.h>

void raceResults(double times[], int size, double* firstPlace, double* average) {
    if (size == 0) {
        *firstPlace = -1;
        *average = 0;
        return;
    }
    *firstPlace = times[0];
    double totalTime = 0;
    for (int i = 0; i < size; i++) {
        if (times[i] < *firstPlace)
            *firstPlace = times[i];
        totalTime += times[i];
    }
    *average = totalTime / size;
}

int main() {
    double times[] = {12.5, 10.0, 11.2, 13.3};
    double firstPlace, average;
    raceResults(times, 4, &firstPlace, &average);
    printf("First Place Time: %.2f, Average Time: %.2f\n", firstPlace, average);
    return 0;
}

6. A time traveller collects artifacts from different years. Each artifact has a year associated with it. Your task is to find the range of years from the earliest to the latest artifact collected.

Input Format

• A list of integers representing the years.

Output Format

• An integer representing the range of years (latest year - earliest year).

Input: [1995, 2001, 1985, 2010] Output: 25

Python

def year_range(artifacts):
    return max(artifacts) - min(artifacts)

print(year_range([1995, 2001, 1985, 2010]))

Java

public class Main {
    public static int yearRange(int[] artifacts) {
        int minYear = artifacts[0];
        int maxYear = artifacts[0];
        for (int year : artifacts) {
            if (year < minYear)
                minYear = year;
            if (year > maxYear)
                maxYear = year;
        }
        return maxYear - minYear;
    }

    public static void main(String[] args) {
        System.out.println(yearRange(new int[]{1995, 2001, 1985, 2010}));
    }
}

C

#include <stdio.h>

int yearRange(int artifacts[], int size) {
    int minYear = artifacts[0];
    int maxYear = artifacts[0];
    for (int i = 1; i < size; i++) {
        if (artifacts[i] < minYear)
            minYear = artifacts[i];
        if (artifacts[i] > maxYear)
            maxYear = artifacts[i];
    }
    return maxYear - minYear;
}

int main() {
    int artifacts[] = {1995, 2001, 1985, 2010};
    printf("%d\n", yearRange(artifacts, 4));
    return 0;
}

7. In a mysterious library, each book has a unique ID, and some books are quite old. Your task is to find the ID of the oldest book and the average ID of all the books.

Input Format

• A list of integers as series I.D.s for each book.

Output Format

• Two integers: the ID of the oldest book and the average ID (rounded down)

Example

Input: [1001, 1002, 999, 1003] Output: (999, 1001)

‍Python

def book_info(books):
    oldest = min(books)
    average = sum(books) // len(books)
    return oldest, average

print(book_info([1001, 1002, 999, 1003]))

Java

public class Main {
    public static int[] bookInfo(int[] books) {
        int oldest = books[0];
        int total = 0;
        for (int id : books) {
            if (id < oldest)
                oldest = id;
            total += id;
        }
        int average = total / books.length;
        return new int[]{oldest, average};
    }

    public static void main(String[] args) {
        int[] result = bookInfo(new int[]{1001, 1002, 999, 1003});
        System.out.println("(" + result[0] + ", " + result[1] + ")");
    }
}

C

#include <stdio.h>

void bookInfo(int books[], int size, int* oldest, int* average) {
    *oldest = books[0];
    int total = 0;
    for (int i = 0; i < size; i++) {
        if (books[i] < *oldest)
            *oldest = books[i];
        total += books[i];
    }
    *average = total / size;
}

int main() {
    int books[] = {1001, 1002, 999, 1003};
    int oldest, average;
    bookInfo(books, 4, &oldest, &average);
    printf("Oldest ID: %d, Average ID: %d\n", oldest, average);
    return 0;
}

8. A dragon hoards treasures in different forms, each with a specific value. Your task is to calculate the total value of the treasures and find the highest value among them.

Input Format

• A list of integers representing the values of the treasures.

Output Format

• Two integers: the total value and the highest value.

Example

Input: [200, 500, 1000, 300] Output: (2000, 1000)

Python

def dragon_hoard(treasures):
    total_value = sum(treasures)
    highest_value = max(treasures)
    return total_value, highest_value

print(dragon_hoard([200, 500, 1000, 300]))

Java

public class Main {
    public static int[] dragonHoard(int[] treasures) {
        int totalValue = 0;
        int highestValue = treasures[0];
        for (int value : treasures) {
            totalValue += value;
            if (value > highestValue)
                highestValue = value;
        }
        return new int[]{totalValue, highestValue};
    }

    public static void main(String[] args) {
        int[] result = dragonHoard(new int[]{200, 500, 1000, 300});
        System.out.println("(" + result[0] + ", " + result[1] + ")");
    }
}

C

#include <stdio.h>

void dragonHoard(int treasures[], int size, int* totalValue, int* highestValue) {
    *totalValue = 0;
    *highestValue = treasures[0];
    for (int i = 0; i < size; i++) {
        *totalValue += treasures[i];
        if (treasures[i] > *highestValue)
            *highestValue = treasures[i];
    }
}

int main() {
    int treasures[] = {200, 500, 1000, 300};
    int totalValue, highestValue;
    dragonHoard(treasures, 4, &totalValue, &highestValue);
    printf("Total Value: %d, Highest Value: %d\n", totalValue, highestValue);
    return 0;
}

These challenges are substantially more complex, encompassing a selection of combinations, dynamic programming, or sequence analysis challenges. They assess your capability to optimize solutions and to deal with edge cases systematically.

9. In a magical forest, there is an animal, and each animal is identified with a unique identifier (ID). Few animals have decided to pair based on their ID. Your task is to find all the unique pairs of animal IDs possible.

Input Format

• A list of integers, which represent animal ids.

Output Format

• A row of unique pairs of animal IDs.

Input: [1, 2, 3] Output: [(1, 2), (1, 3), (2, 3)]

Python

def unique_pairs(animal_ids):
    pairs = []
    for i in range(len(animal_ids)):
        for j in range(i + 1, len(animal_ids)):
            pairs.append((animal_ids[i], animal_ids[j]))
    return pairs

print(unique_pairs([1, 2, 3]))

Java

import java.util.ArrayList;
import java.util.List;

public class Main {
    public static List<int[]> uniquePairs(int[] animalIds) {
        List<int[]> pairs = new ArrayList<>();
        for (int i = 0; i < animalIds.length; i++) {
            for (int j = i + 1; j < animalIds.length; j++) {
                pairs.add(new int[]{animalIds[i], animalIds[j]});
            }
        }
        return pairs;
    }

    public static void main(String[] args) {
        List<int[]> result = uniquePairs(new int[]{1, 2, 3});
        for (int[] pair : result) {
            System.out.println("Pair: " + pair[0] + ", " + pair[1]);
        }
    }
}

C

#include <stdio.h>

void uniquePairs(int animalIds[], int size) {
    for (int i = 0; i < size; i++) {
        for (int j = i + 1; j < size; j++) {
            printf("Pair: %d, %d\n", animalIds[i], animalIds[j]);
        }
    }
}

int main() {
    int animalIds[] = {1, 2, 3};
    uniquePairs(animalIds, 3);
    return 0;
}

10. In a village, there are treasure chests at different locations. Each chest has some number of coins, and some treasure chests are cursed. Cursed chests give negative coins, in contrast to ordinary ones. The goal is to figure out the most profit you can make by taking a consecutive series of treasure chests.

Input Format

• A list of integers representing the coins in each chest.

Output Format

• An integer representing the maximum sum of coins from consecutive chests.

Example

Input: [2, -3, 4, -1, 2, 1, -5, 4] Output: 6

Python

def max_treasure(chests):
    max_sum = current_sum = 0
    for coins in chests:
        current_sum += coins
        if current_sum < 0:
            current_sum = 0
        max_sum = max(max_sum, current_sum)
    return max_sum

print(max_treasure([2, -3, 4, -1, 2, 1, -5, 4]))

Java

public class Main {
    public static int maxTreasure(int[] chests) {
        int maxSum = 0, currentSum = 0;
        for (int coins : chests) {
            currentSum += coins;
            if (currentSum < 0) currentSum = 0;
            maxSum = Math.max(maxSum, currentSum);
        }
        return maxSum;
    }

    public static void main(String[] args) {
        System.out.println(maxTreasure(new int[]{2, -3, 4, -1, 2, 1, -5, 4}));
    }
}

C

#include <stdio.h>

int maxTreasure(int chests[], int size) {
    int maxSum = 0, currentSum = 0;
    for (int i = 0; i < size; i++) {
        currentSum += chests[i];
        if (currentSum < 0) currentSum = 0;
        if (currentSum > maxSum) maxSum = currentSum;
    }
    return maxSum;
}

int main() {
    int chests[] = {2, -3, 4, -1, 2, 1, -5, 4};
    printf("%d\n", maxTreasure(chests, 8));
    return 0;
}

11. A "weird number" is defined as a number that is not divisible by a given integer KKK, but the sum of its digits is divisible by KKK. Your task is to find the first weird number in the array. If none exists, return -1.

Input Format:

• An array of integers
• An integer KKK

Output Format:

• The first weird number, or -1 in the absence of any.

Example:
Input: [12, 34, 56, 78], K = 3
Output: 12

Python

def weird_number(arr, k):
    for num in arr:
        if num % k != 0 and sum(int(d) for d in str(num)) % k == 0:
            return num
    return -1

print(weird_number([12, 34, 56, 78], 3))

Java

public class Main {
    public static int weirdNumber(int[] arr, int k) {
        for (int num : arr) {
            int sumDigits = 0, temp = num;
            while (temp > 0) {
                sumDigits += temp % 10;
                temp /= 10;
            }
            if (num % k != 0 && sumDigits % k == 0)
                return num;
        }
        return -1;
    }

    public static void main(String[] args) {
        int[] arr = {12, 34, 56, 78};
        System.out.println(weirdNumber(arr, 3));
    }
}

C

#include <stdio.h>

int sumDigits(int num) {
    int sum = 0;
    while (num > 0) {
        sum += num % 10;
        num /= 10;
    }
    return sum;
}

int weirdNumber(int arr[], int size, int k) {
    for (int i = 0; i < size; i++) {
        if (arr[i] % k != 0 && sumDigits(arr[i]) % k == 0)
            return arr[i];
    }
    return -1;
}

int main() {
    int arr[] = {12, 34, 56, 78};
    printf("%d\n", weirdNumber(arr, 4, 3));
    return 0;
}

12. Given an array of integers, you need to find the longest length of a subsequence such that the sum of that subsequence is divisible by a number KKK.

Input Format:

• An array of integers
• An integer KKK

Output Format:

• The maximum length of a subsequence whose sum is evenly divisible by KKK
• Returns 0 if there are no such subsequences.

Example:
Input: [1, 2, 3, 4, 5], K = 3
Output: 3

Python

def longest_subseq_divisible(arr, k):
    n = len(arr)
    dp = [0] * k
    for num in arr:
        temp = dp[:]
        for r in range(k):
            new_rem = (r + num) % k
            temp[new_rem] = max(temp[new_rem], dp[r] + 1)
        temp[num % k] = max(temp[num % k], 1)
        dp = temp
    return dp[0]

print(longest_subseq_divisible([1, 2, 3, 4, 5], 3))

Java

public class Main {
    public static int longestSubseqDivisible(int[] arr, int k) {
        int[] dp = new int[k];
        for (int num : arr) {
            int[] temp = dp.clone();
            for (int r = 0; r < k; r++) {
                int newRem = (r + num) % k;
                temp[newRem] = Math.max(temp[newRem], dp[r] + 1);
            }
            temp[num % k] = Math.max(temp[num % k], 1);
            dp = temp;
        }
        return dp[0];
    }

    public static void main(String[] args) {
        int[] arr = {1, 2, 3, 4, 5};
        System.out.println(longestSubseqDivisible(arr, 3));
    }
}

C

#include <stdio.h>

int max(int a, int b) {
    return (a > b) ? a : b;
}

int longestSubseqDivisible(int arr[], int n, int k) {
    int dp[k];
    for (int i = 0; i < k; i++) dp[i] = 0;
    for (int i = 0; i < n; i++) {
        int temp[k];
        for (int j = 0; j < k; j++) temp[j] = dp[j];
        for (int r = 0; r < k; r++) {
            int newRem = (r + arr[i]) % k;
            temp[newRem] = max(temp[newRem], dp[r] + 1);
        }
        temp[arr[i] % k] = max(temp[arr[i] % k], 1);
        for (int j = 0; j < k; j++) dp[j] = temp[j];
    }
    return dp[0];
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    printf("%d\n", longestSubseqDivisible(arr, 5, 3));
    return 0;
}

To succeed at the coding assessment, you will need more than just a technical background; smart preparation, swift and efficient problem solving, and the ability to execute with confidence. Below are some strategies and best practices that have been proven to work for students.

1. Master the Basics

• Make sure you have a good understanding of the fundamentals of programming: loops, conditionals, data types, and functions.
• Get comfortable practicing common data structures (arrays, strings, linked lists) and algorithms (sorting, searching, recursion).

2. Practice with Realistic Problems

• Use online platforms like LeetCode, HackerRank, etc, to practice solving problems similar to those asked by Accenture.
• Be mindful of focusing on questions that require you to write a full program, as the test expects you to generate your solution from scratch.

3. Simulate the Test Environment

• Do mock testing with a time limit, so you can get used to the real 45-minute, two-question environment.
• Mock practice coding assessments with the same programming language and the same way of representing inputs and outputs, as you will do in a real coding assessment.

4. Focus on Coding Efficiency and Speed

• Write clean, readable code with clear variable names and comments.
• Prioritize correct logic first, then optimize for efficiency if time allows.
• Test your code with edge cases to ensure reliability.

5. Improve Problem-Solving Techniques

• Divide complicated problems into smaller pieces and address them one step at a time.
• Use pseudo code and logical steps to work through a problem before going directly to coding.
• Be methodical when debugging; trace errors using print statements or built-in debuggers.

6. Manage Your Time Wisely

• Read both questions at the start and start with the one you feel most confident about.
• Don’t get stuck if you’re stuck on one question for too long; move to the next and return if time allows.
• Aim to fully solve at least one question and partially solve the other for the best chance of clearing the round.

7. Prepare for the Assessment Platform

• Familiarize yourself with the CoCubes platform (commonly used by Accenture) or any other specified platform.
• Review how to submit code, run test cases, and understand error messages.

8. Seek Feedback and Review

• If you can, take part in mock sessions or coding workshops offered by PrepInsta or other platforms.
• Have someone review your code or your overall approach to solving a problem.
• You can also consider a resume review and interview training, as both will improve your overall application.

9. Stay Calm and Positive

• When doing the test, go in with a clear mindset and trust what you practiced and have been preparing.
• Think back, practice, and smart strategies matter.

As you progress through the coding assessment for experience, following the steps and suggestions offered here should leave you confident in your pursuit of obtaining an offer at Accenture.

A successful action in Accenture's coding assessment isn't simply memorising the answers. It is built around solid programming fundamentals, through solid reasoning/problem solving, and through practice! By getting familiar with the variety of questions, from easy to challenging, and strengthening your knowledge of data structures, algorithms, and coding techniques, you set yourself up to perform confidently, even under time pressure.

What This Blog Has Covered:

• An overview of Accenture’s coding test pattern, including duration, number of questions, and difficulty levels.
• Rules and guidelines to follow for a smooth and successful test attempt.
• Step-by-step solutions in Python, Java, and C for beginner, intermediate, and advanced coding questions.
• Insights into common topics and data structures tested, such as arrays, strings, dynamic programming, and logic puzzles.
• Tips on scoring strategy, time management, and coding efficiency to maximize your performance.
• Proven preparation techniques and practice methods to improve problem-solving skills and test confidence.

By implementing these strategies and practicing systematically, you will not only clear the coding round but also be a self-assured and able candidate for your dream role at Accenture.

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Talk to a career expert

1. What is pseudo code, and why is it used in Accenture coding assessments?

Pseudo-code is a simple way to describe an algorithm using the structure of programming languages without worrying about syntax. It helps assess your logical thinking and problem-solving skills.‍

2. Are there any specific Accenture ASE coding questions I should know about?

Accenture ASE coding questions usually focus on programming basics and may include topics related to automation and testing, along with general coding challenges.

3. Are Accenture coding questions repeated from previous years?

Although Accenture does introduce new questions, you can expect to see the same concept or a variation of previous years' questions. Practicing past questions is useful, but rather than memorize solutions, focus on concepts instead.

4. How difficult is the Accenture coding round?

The difficulty level is generally moderate to high. Most candidates can expect one question of medium difficulty and one that may be more challenging. Strong fundamentals and consistent practice are key to handling both.

5. What is the structure of the Accenture coding assessment?

The test typically consists of two coding questions to be solved in 45 minutes. Python, Java, C, and C++ are among the many programming languages available to you. The assessment is non-adaptive, and you must write code from scratch.

6. What is the Accenture Cognitive Assessment?

The Cognitive Assessment evaluates your aptitude, logical reasoning, and problem-solving abilities. It is usually a separate section from the coding round and must be cleared to advance in the hiring process.

7. Is there a difference between on-campus and off-campus Accenture coding tests?

The structure and question types are generally similar for both on-campus and off-campus placements. However, the interview process or platform used may vary slightly.

8. Do I need to know advanced algorithms or data structures?

Most questions focus on core programming concepts, arrays, strings, and basic data structures. However, for advanced roles, you may encounter questions on algorithms, OOP, or system design.

9. How is my code evaluated?

Your code is automatically tested against sample and hidden test cases. You need to pass all test cases for at least one question and as many as possible for the other to maximize your chances of selection.

10. What if I get stuck on a question during the test?

Manage your time wisely. If you're stuck on a question, move on to the next question and come back to it if there's time. You should plan to complete one question and partly complete a second question.

11. Can I use online resources during the test?

No, outside help or resources cannot be used. Cheating and/or plagiarism would result in disqualification.

12. What happens after I clear the coding round?

Successful candidates are typically invited to further technical and HR interviews, where problem-solving skills, technical knowledge, and communication abilities are assessed.